Solve for x log base a of x=2 log base a of 3+ log base a of 5

$\log_{a} (x) = 2 \log_{a} (3) + \log_{a} (5)$

Simplify the right side.

Simplify $2 \log_{a} (3) + \log_{a} (5)$ .

Simplify each term.

Simplify $2 \log_{a} (3)$ by moving $2$ inside the logarithm.

$\log_{a} (x) = \log_{a} (3^{2}) + \log_{a} (5)$

Raise $3$ to the power of $2$ .

$\log_{a} (x) = \log_{a} (9) + \log_{a} (5)$

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{a} (x) = \log_{a} (9 \cdot 5)$

Multiply $9$ by $5$ .

$\log_{a} (x) = \log_{a} (45)$

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

$x = 45$