Solve for x log base x of 121=2

$\log_{x} (121) = 2$

Step 1

Rewrite $\log_{x} (121) = 2$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$x^{2} = 121$

Step 2

Solve for $x$ .

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{121}$

Simplify $\pm \sqrt{121}$ .

Rewrite $121$ as $11^{2}$ .

$x = \pm \sqrt{11^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 11$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 11$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 11$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 11, - 11$

Step 3

Exclude the solutions that do not make $\log_{x} (121) = 2$ true.

$x = 11$

Solve for x log base x of 121=2

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