Solve for x log base x of 4=-2

$\log_{x} (4) = - 2$

Rewrite $\log_{x} (4) = - 2$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$x^{- 2} = 4$

Solve for $x$ .

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{x^{2}} = 4$

Find the LCD of the terms in the equation.

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$x^{2}, 1$

The LCM of one and any expression is the expression.

$x^{2}$

Multiply each term in $\frac{1}{x^{2}} = 4$ by $x^{2}$ to eliminate the fractions.

Multiply each term in $\frac{1}{x^{2}} = 4$ by $x^{2}$ .

$\frac{1}{x^{2}} x^{2} = 4 x^{2}$

Simplify the left side.

Cancel the common factor of $x^{2}$ .

Cancel the common factor.

$\frac{1}{x^{2}} x^{2} = 4 x^{2}$

Rewrite the expression.

$1 = 4 x^{2}$

Solve the equation.

Rewrite the equation as $4 x^{2} = 1$ .

$4 x^{2} = 1$

Divide each term in $4 x^{2} = 1$ by $4$ and simplify.

Divide each term in $4 x^{2} = 1$ by $4$ .

$\frac{4 x^{2}}{4} = \frac{1}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x^{2}}{4} = \frac{1}{4}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{1}{4}$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{\frac{1}{4}}$

Simplify $\pm \sqrt{\frac{1}{4}}$ .

Rewrite $\sqrt{\frac{1}{4}}$ as $\frac{\sqrt{1}}{\sqrt{4}}$ .

$x = \pm \frac{\sqrt{1}}{\sqrt{4}}$

Any root of $1$ is $1$ .

$x = \pm \frac{1}{\sqrt{4}}$

Simplify the denominator.

Rewrite $4$ as $2^{2}$ .

$x = \pm \frac{1}{\sqrt{2^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm \frac{1}{2}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \frac{1}{2}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \frac{1}{2}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \frac{1}{2}, - \frac{1}{2}$

Exclude the solutions that do not make $\log_{x} (4) = - 2$ true.

$x = \frac{1}{2}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{2}$

Decimal Form:

$x = 0.5$

Solve for x log base x of 4=-2

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