Solve for x log base x of 625=4

$\log_{x} (625) = 4$

Rewrite $\log_{x} (625) = 4$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$x^{4} = 625$

Solve for $x$ .

Take the 4th root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt[4]{625}$

Simplify $\pm \sqrt[4]{625}$ .

Rewrite $625$ as $5^{4}$ .

$x = \pm \sqrt[4]{5^{4}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 5$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 5$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 5$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 5, - 5$

Exclude the solutions that do not make $\log_{x} (625) = 4$ true.

$x = 5$

Solve for x log base x of 625=4

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