Solve for x log base x of 7=1/2

$\log_{x} (7) = \frac{1}{2}$

Step 1

Rewrite $\log_{x} (7) = \frac{1}{2}$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$x^{\frac{1}{2}} = 7$

Step 2

Solve for $x$ .

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = 7^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = 7^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = 7^{2}$

Rewrite the expression.

$x^{1} = 7^{2}$

Simplify.

$x = 7^{2}$

Simplify the right side.

Raise $7$ to the power of $2$ .

$x = 49$

Solve for x log base x of 7=1/2

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