Solve for x log of 5-2x=0

$\log (5 - 2 x) = 0$

Step 1

Rewrite $\log (5 - 2 x) = 0$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$10^{0} = 5 - 2 x$

Step 2

Solve for $x$ .

Rewrite the equation as $5 - 2 x = 10^{0}$ .

$5 - 2 x = 10^{0}$

Anything raised to $0$ is $1$ .

$5 - 2 x = 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$- 2 x = 1 - 5$

Subtract $5$ from $1$ .

$- 2 x = - 4$

Divide each term in $- 2 x = - 4$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 4$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 4}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 4}{- 2}$

Divide $x$ by $1$ .

$x = \frac{- 4}{- 2}$

Simplify the right side.

Divide $- 4$ by $- 2$ .

$x = 2$

Solve for x log of 5-2x=0

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