Solve for x log of 5+ log of 2=x

$\log (5) + \log (2) = x$

Step 1

Rewrite the equation as $x = \log (5) + \log (2)$ .

$x = \log (5) + \log (2)$

Step 2

Simplify $\log (5) + \log (2)$ .

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$x = \log (5 \cdot 2)$

Multiply $5$ by $2$ .

$x = \log (10)$

Logarithm base $10$ of $10$ is $1$ .

$x = 1$