Solve for x log of x-2=1

$\log (x - 2) = 1$

Rewrite $\log (x - 2) = 1$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$10^{1} = x - 2$

Solve for $x$ .

Rewrite the equation as $x - 2 = 10^{1}$ .

$x - 2 = 10$

Move all terms not containing $x$ to the right side of the equation.

Add $2$ to both sides of the equation.

$x = 10 + 2$

Add $10$ and $2$ .

$x = 12$

Solve for x log of x-2=1

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