Solve for x - log of x=4.1

$- \log (x) = 4.1$

Divide each term in $- \log (x) = 4.1$ by $- 1$ and simplify.

Divide each term in $- \log (x) = 4.1$ by $- 1$ .

$\frac{- \log (x)}{- 1} = \frac{4.1}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{\log (x)}{1} = \frac{4.1}{- 1}$

Divide $\log (x)$ by $1$ .

$\log (x) = \frac{4.1}{- 1}$

Simplify the right side.

Divide $4.1$ by $- 1$ .

$\log (x) = - 4.1$

Rewrite $\log (x) = - 4.1$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$10^{- 4.1} = x$

Solve for $x$ .

Rewrite the equation as $x = 10^{- 4.1}$ .

$x = 10^{- 4.1}$

Simplify $10^{- 4.1}$ .

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$x = \frac{1}{10^{4.1}}$

Raise $10$ to the power of $4.1$ .

$x = \frac{1}{12589.25411794}$

Divide $1$ by $12589.25411794$ .

$x = 0.00007943$

Solve for x - log of x=4.1

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