Solve for x log of x+8 = log of x+ log of 8

$\log (x + 8) = \log (x) + \log (8)$

Step 1

Simplify the right side.

Simplify $\log (x) + \log (8)$ .

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log (x + 8) = \log (x \cdot 8)$

Move $8$ to the left of $x$ .

$\log (x + 8) = \log (8 x)$

Step 2

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

$x + 8 = 8 x$

Step 3

Solve for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$x + 8 - 8 x = 0$

Subtract $8 x$ from $x$ .

$- 7 x + 8 = 0$

Subtract $8$ from both sides of the equation.

$- 7 x = - 8$

Divide each term in $- 7 x = - 8$ by $- 7$ and simplify.

Divide each term in $- 7 x = - 8$ by $- 7$ .

$\frac{- 7 x}{- 7} = \frac{- 8}{- 7}$

Simplify the left side.

Cancel the common factor of $- 7$ .

Cancel the common factor.

$\frac{- 7 x}{- 7} = \frac{- 8}{- 7}$

Divide $x$ by $1$ .

$x = \frac{- 8}{- 7}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{8}{7}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{8}{7}$

Decimal Form:

$x = 1.\overline{142857}$

Mixed Number Form:

$x = 1 \frac{1}{7}$