Solve for x natural log of 2+x=1

$\ln (2 + x) = 1$

Step 1

To solve for $x$ , rewrite the equation using properties of logarithms.

$e^{\ln (2 + x)} = e^{1}$

Step 2

Rewrite $\ln (2 + x) = 1$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$e^{1} = 2 + x$

Step 3

Solve for $x$ .

Rewrite the equation as $2 + x = e^{1}$ .

$2 + x = e$

Subtract $2$ from both sides of the equation.

$x = e - 2$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = e - 2$

Decimal Form:

$x = 0.71828182 \dots$

Solve for x natural log of 2+x=1

Related Questions

Support LCMGCF.com by disabling your adblocker.