Solve for x natural log of square root of x-8=5

$\ln (\sqrt{x - 8}) = 5$

To solve for $x$ , rewrite the equation using properties of logarithms.

$e^{\ln (\sqrt{x - 8})} = e^{5}$

Rewrite $\ln (\sqrt{x - 8}) = 5$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$e^{5} = \sqrt{x - 8}$

Solve for $x$ .

Rewrite the equation as $\sqrt{x - 8} = e^{5}$ .

$\sqrt{x - 8} = e^{5}$

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{x - 8}}^{2} = {(e^{5})}^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x - 8}$ as ${(x - 8)}^{\frac{1}{2}}$ .

${({(x - 8)}^{\frac{1}{2}})}^{2} = {(e^{5})}^{2}$

Simplify the left side.

Simplify ${({(x - 8)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(x - 8)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x - 8)}^{\frac{1}{2} \cdot 2} = {(e^{5})}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(x - 8)}^{\frac{1}{2} \cdot 2} = {(e^{5})}^{2}$

Rewrite the expression.

${(x - 8)}^{1} = {(e^{5})}^{2}$

Simplify.

$x - 8 = {(e^{5})}^{2}$

Simplify the right side.

Multiply the exponents in ${(e^{5})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x - 8 = e^{5 \cdot 2}$

Multiply $5$ by $2$ .

$x - 8 = e^{10}$

Add $8$ to both sides of the equation.

$x = e^{10} + 8$

The result can be shown in multiple forms.

Exact Form:

$x = e^{10} + 8$

Decimal Form:

$x = 22034.46579480 \dots$

Solve for x natural log of square root of x-8=5

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