Solve for x natural log of x+1- natural log of x-2 = natural log of x

$\ln (x + 1) - \ln (x - 2) = \ln (x)$

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\ln (\frac{x + 1}{x - 2}) = \ln (x)$

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

$\frac{x + 1}{x - 2} = x$

Solve for $x$ .

Find the LCD of the terms in the equation.

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$x - 2, 1$

Remove parentheses.

$x - 2, 1$

The LCM of one and any expression is the expression.

$x - 2$

Multiply each term in $\frac{x + 1}{x - 2} = x$ by $x - 2$ to eliminate the fractions.

Multiply each term in $\frac{x + 1}{x - 2} = x$ by $x - 2$ .

$\frac{x + 1}{x - 2} (x - 2) = x (x - 2)$

Simplify the left side.

Cancel the common factor of $x - 2$ .

Cancel the common factor.

$\frac{x + 1}{x - 2} (x - 2) = x (x - 2)$

Rewrite the expression.

$x + 1 = x (x - 2)$

Simplify the right side.

Apply the distributive property.

$x + 1 = x \cdot x + x \cdot - 2$

Simplify the expression.

Multiply $x$ by $x$ .

$x + 1 = x^{2} + x \cdot - 2$

Move $- 2$ to the left of $x$ .

$x + 1 = x^{2} - 2 x$

Solve the equation.

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x^{2} - 2 x = x + 1$

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$x^{2} - 2 x - x = 1$

Subtract $x$ from $- 2 x$ .

$x^{2} - 3 x = 1$

Subtract $1$ from both sides of the equation.

$x^{2} - 3 x - 1 = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 1$ , $b = - 3$ , and $c = - 1$ into the quadratic formula and solve for $x$ .

$\frac{3 \pm \sqrt{{(- 3)}^{2} - 4 \cdot (1 \cdot - 1)}}{2 \cdot 1}$

Simplify.

Simplify the numerator.

Raise $- 3$ to the power of $2$ .

$x = \frac{3 \pm \sqrt{9 - 4 \cdot 1 \cdot - 1}}{2 \cdot 1}$

Multiply $- 4$ by $1$ .

$x = \frac{3 \pm \sqrt{9 - 4 \cdot - 1}}{2 \cdot 1}$

Multiply $- 4$ by $- 1$ .

$x = \frac{3 \pm \sqrt{9 + 4}}{2 \cdot 1}$

Add $9$ and $4$ .

$x = \frac{3 \pm \sqrt{13}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$x = \frac{3 \pm \sqrt{13}}{2}$

The final answer is the combination of both solutions.

$x = \frac{3 + \sqrt{13}}{2}, \frac{3 - \sqrt{13}}{2}$

Exclude the solutions that do not make $\ln (x + 1) - \ln (x - 2) = \ln (x)$ true.

$x = \frac{3 + \sqrt{13}}{2}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{3 + \sqrt{13}}{2}$

Decimal Form:

$x = 3.30277563 \dots$

Solve for x natural log of x+1- natural log of x-2 = natural log of x

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