Solve for x natural log of x-5- natural log of x+4 = natural log of x-1- natural log of x+2

$\ln (x - 5) - \ln (x + 4) = \ln (x - 1) - \ln (x + 2)$

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\ln (\frac{x - 5}{x + 4}) = \ln (x - 1) - \ln (x + 2)$

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\ln (\frac{x - 5}{x + 4}) = \ln (\frac{x - 1}{x + 2})$

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

$\frac{x - 5}{x + 4} = \frac{x - 1}{x + 2}$

Solve for $x$ .

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

$(x - 5) (x + 2) = (x + 4) (x - 1)$

Solve the equation for $x$ .

Simplify $(x - 5) (x + 2)$ .

Start simplifying.

$0 + 0 + (x - 5) (x + 2) = (x + 4) (x - 1)$

Simplify by adding zeros.

$(x - 5) (x + 2) = (x + 4) (x - 1)$

Expand $(x - 5) (x + 2)$ using the FOIL Method.

Apply the distributive property.

$x (x + 2) - 5 (x + 2) = (x + 4) (x - 1)$

Apply the distributive property.

$x \cdot x + x \cdot 2 - 5 (x + 2) = (x + 4) (x - 1)$

Apply the distributive property.

$x \cdot x + x \cdot 2 - 5 x - 5 \cdot 2 = (x + 4) (x - 1)$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 2 - 5 x - 5 \cdot 2 = (x + 4) (x - 1)$

Move $2$ to the left of $x$ .

$x^{2} + 2 \cdot x - 5 x - 5 \cdot 2 = (x + 4) (x - 1)$

Multiply $- 5$ by $2$ .

$x^{2} + 2 x - 5 x - 10 = (x + 4) (x - 1)$

Subtract $5 x$ from $2 x$ .

$x^{2} - 3 x - 10 = (x + 4) (x - 1)$

Simplify $(x + 4) (x - 1)$ .

Expand $(x + 4) (x - 1)$ using the FOIL Method.

Apply the distributive property.

$x^{2} - 3 x - 10 = x (x - 1) + 4 (x - 1)$

Apply the distributive property.

$x^{2} - 3 x - 10 = x \cdot x + x \cdot - 1 + 4 (x - 1)$

Apply the distributive property.

$x^{2} - 3 x - 10 = x \cdot x + x \cdot - 1 + 4 x + 4 \cdot - 1$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} - 3 x - 10 = x^{2} + x \cdot - 1 + 4 x + 4 \cdot - 1$

Move $- 1$ to the left of $x$ .

$x^{2} - 3 x - 10 = x^{2} - 1 \cdot x + 4 x + 4 \cdot - 1$

Rewrite $- 1 x$ as $- x$ .

$x^{2} - 3 x - 10 = x^{2} - x + 4 x + 4 \cdot - 1$

Multiply $4$ by $- 1$ .

$x^{2} - 3 x - 10 = x^{2} - x + 4 x - 4$

Add $- x$ and $4 x$ .

$x^{2} - 3 x - 10 = x^{2} + 3 x - 4$

Move all terms containing $x$ to the left side of the equation.

Subtract $x^{2}$ from both sides of the equation.

$x^{2} - 3 x - 10 - x^{2} = 3 x - 4$

Subtract $3 x$ from both sides of the equation.

$x^{2} - 3 x - 10 - x^{2} - 3 x = - 4$

Combine the opposite terms in $x^{2} - 3 x - 10 - x^{2} - 3 x$ .

Subtract $x^{2}$ from $x^{2}$ .

$- 3 x - 10 + 0 - 3 x = - 4$

Add $- 3 x - 10$ and $0$ .

$- 3 x - 10 - 3 x = - 4$

Subtract $3 x$ from $- 3 x$ .

$- 6 x - 10 = - 4$

Move all terms not containing $x$ to the right side of the equation.

Add $10$ to both sides of the equation.

$- 6 x = - 4 + 10$

Add $- 4$ and $10$ .

$- 6 x = 6$

Divide each term in $- 6 x = 6$ by $- 6$ and simplify.

Divide each term in $- 6 x = 6$ by $- 6$ .

$\frac{- 6 x}{- 6} = \frac{6}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 x}{- 6} = \frac{6}{- 6}$

Divide $x$ by $1$ .

$x = \frac{6}{- 6}$

Simplify the right side.

Divide $6$ by $- 6$ .

$x = - 1$

Exclude the solutions that do not make $\ln (x - 5) - \ln (x + 4) = \ln (x - 1) - \ln (x + 2)$ true.

$No solution$

Solve for x natural log of x-5- natural log of x+4 = natural log of x-1- natural log of x+2

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