Solve for x q(x)=1/2x-3 , q(x)=-4

$q (x) = \frac{1}{2} x - 3$ , $q (x) = - 4$

Step 1

Substitute $- 4$ for $q (x)$ .

$- 4 = \frac{1}{2} x - 3$

Step 2

Solve for $x$ .

Rewrite the equation as $\frac{1}{2} x - 3 = - 4$ .

$\frac{1}{2} x - 3 = - 4$

Combine $\frac{1}{2}$ and $x$ .

$\frac{x}{2} - 3 = - 4$

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$\frac{x}{2} = - 4 + 3$

Add $- 4$ and $3$ .

$\frac{x}{2} = - 1$

Multiply both sides of the equation by $2$ .

$2 \frac{x}{2} = 2 \cdot - 1$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$2 \frac{x}{2} = 2 \cdot - 1$

Rewrite the expression.

$x = 2 \cdot - 1$

Simplify the right side.

Multiply $2$ by $- 1$ .

$x = - 2$