Solve for x square root of 15x+10=2x+3

$\sqrt{15 x + 10} = 2 x + 3$

Step 1

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{15 x + 10}}^{2} = {(2 x + 3)}^{2}$

Step 2

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{15 x + 10}$ as ${(15 x + 10)}^{\frac{1}{2}}$ .

${({(15 x + 10)}^{\frac{1}{2}})}^{2} = {(2 x + 3)}^{2}$

Simplify the left side.

Simplify ${({(15 x + 10)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(15 x + 10)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(15 x + 10)}^{\frac{1}{2} \cdot 2} = {(2 x + 3)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(15 x + 10)}^{\frac{1}{2} \cdot 2} = {(2 x + 3)}^{2}$

Rewrite the expression.

${(15 x + 10)}^{1} = {(2 x + 3)}^{2}$

Simplify.

$15 x + 10 = {(2 x + 3)}^{2}$

Simplify the right side.

Simplify ${(2 x + 3)}^{2}$ .

Rewrite ${(2 x + 3)}^{2}$ as $(2 x + 3) (2 x + 3)$ .

$15 x + 10 = (2 x + 3) (2 x + 3)$

Expand $(2 x + 3) (2 x + 3)$ using the FOIL Method.

Apply the distributive property.

$15 x + 10 = 2 x (2 x + 3) + 3 (2 x + 3)$

Apply the distributive property.

$15 x + 10 = 2 x (2 x) + 2 x \cdot 3 + 3 (2 x + 3)$

Apply the distributive property.

$15 x + 10 = 2 x (2 x) + 2 x \cdot 3 + 3 (2 x) + 3 \cdot 3$

Simplify and combine like terms.

Simplify each term.

Rewrite using the commutative property of multiplication.

$15 x + 10 = 2 \cdot 2 x \cdot x + 2 x \cdot 3 + 3 (2 x) + 3 \cdot 3$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$15 x + 10 = 2 \cdot 2 (x \cdot x) + 2 x \cdot 3 + 3 (2 x) + 3 \cdot 3$

Multiply $x$ by $x$ .

$15 x + 10 = 2 \cdot 2 x^{2} + 2 x \cdot 3 + 3 (2 x) + 3 \cdot 3$

Multiply $2$ by $2$ .

$15 x + 10 = 4 x^{2} + 2 x \cdot 3 + 3 (2 x) + 3 \cdot 3$

Multiply $3$ by $2$ .

$15 x + 10 = 4 x^{2} + 6 x + 3 (2 x) + 3 \cdot 3$

Multiply $2$ by $3$ .

$15 x + 10 = 4 x^{2} + 6 x + 6 x + 3 \cdot 3$

Multiply $3$ by $3$ .

$15 x + 10 = 4 x^{2} + 6 x + 6 x + 9$

Add $6 x$ and $6 x$ .

$15 x + 10 = 4 x^{2} + 12 x + 9$

Step 3

Solve for $x$ .

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$4 x^{2} + 12 x + 9 = 15 x + 10$

Move all terms containing $x$ to the left side of the equation.

Subtract $15 x$ from both sides of the equation.

$4 x^{2} + 12 x + 9 - 15 x = 10$

Subtract $15 x$ from $12 x$ .

$4 x^{2} - 3 x + 9 = 10$

Subtract $10$ from both sides of the equation.

$4 x^{2} - 3 x + 9 - 10 = 0$

Subtract $10$ from $9$ .

$4 x^{2} - 3 x - 1 = 0$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 4 \cdot - 1 = - 4$ and whose sum is $b = - 3$ .

Factor $- 3$ out of $- 3 x$ .

$4 x^{2} - 3 x - 1 = 0$

Rewrite $- 3$ as $1$ plus $- 4$

$4 x^{2} + (1 - 4) x - 1 = 0$

Apply the distributive property.

$4 x^{2} + 1 x - 4 x - 1 = 0$

Multiply $x$ by $1$ .

$4 x^{2} + x - 4 x - 1 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(4 x^{2} + x) - 4 x - 1 = 0$

Factor out the greatest common factor (GCF) from each group.

$x (4 x + 1) - (4 x + 1) = 0$

Factor the polynomial by factoring out the greatest common factor, $4 x + 1$ .

$(4 x + 1) (x - 1) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$4 x + 1 = 0$

$x - 1 = 0$

Set $4 x + 1$ equal to $0$ and solve for $x$ .

Set $4 x + 1$ equal to $0$ .

$4 x + 1 = 0$

Solve $4 x + 1 = 0$ for $x$ .

Subtract $1$ from both sides of the equation.

$4 x = - 1$

Divide each term in $4 x = - 1$ by $4$ and simplify.

Divide each term in $4 x = - 1$ by $4$ .

$\frac{4 x}{4} = \frac{- 1}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 1}{4}$

Divide $x$ by $1$ .

$x = \frac{- 1}{4}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{1}{4}$

Set $x - 1$ equal to $0$ and solve for $x$ .

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Add $1$ to both sides of the equation.

$x = 1$

The final solution is all the values that make $(4 x + 1) (x - 1) = 0$ true.

$x = - \frac{1}{4}, 1$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{1}{4}, 1$

Decimal Form:

$x = - 0.25, 1$

Solve for x square root of 15x+10=2x+3

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