Solve for x square root of 2x+4=16

$\sqrt{2 x + 4} = 16$

Step 1

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{2 x + 4}}^{2} = 16^{2}$

Step 2

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2 x + 4}$ as ${(2 x + 4)}^{\frac{1}{2}}$ .

${({(2 x + 4)}^{\frac{1}{2}})}^{2} = 16^{2}$

Simplify the left side.

Simplify ${({(2 x + 4)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(2 x + 4)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(2 x + 4)}^{\frac{1}{2} \cdot 2} = 16^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(2 x + 4)}^{\frac{1}{2} \cdot 2} = 16^{2}$

Rewrite the expression.

${(2 x + 4)}^{1} = 16^{2}$

Simplify.

$2 x + 4 = 16^{2}$

Simplify the right side.

Raise $16$ to the power of $2$ .

$2 x + 4 = 256$

Step 3

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$2 x = 256 - 4$

Subtract $4$ from $256$ .

$2 x = 252$

Divide each term in $2 x = 252$ by $2$ and simplify.

Divide each term in $2 x = 252$ by $2$ .

$\frac{2 x}{2} = \frac{252}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{252}{2}$

Divide $x$ by $1$ .

$x = \frac{252}{2}$

Simplify the right side.

Divide $252$ by $2$ .

$x = 126$