Solve for x square root of 3x-3/4=0

$\sqrt{3 x} - \frac{3}{4} = 0$

Add $\frac{3}{4}$ to both sides of the equation.

$\sqrt{3 x} = \frac{3}{4}$

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{3 x}}^{2} = {(\frac{3}{4})}^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3 x}$ as ${(3 x)}^{\frac{1}{2}}$ .

${({(3 x)}^{\frac{1}{2}})}^{2} = {(\frac{3}{4})}^{2}$

Simplify the left side.

Simplify ${({(3 x)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(3 x)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(3 x)}^{\frac{1}{2} \cdot 2} = {(\frac{3}{4})}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(3 x)}^{\frac{1}{2} \cdot 2} = {(\frac{3}{4})}^{2}$

Rewrite the expression.

${(3 x)}^{1} = {(\frac{3}{4})}^{2}$

Simplify.

$3 x = {(\frac{3}{4})}^{2}$

Simplify the right side.

Simplify ${(\frac{3}{4})}^{2}$ .

Apply the product rule to $\frac{3}{4}$ .

$3 x = \frac{3^{2}}{4^{2}}$

Raise $3$ to the power of $2$ .

$3 x = \frac{9}{4^{2}}$

Raise $4$ to the power of $2$ .

$3 x = \frac{9}{16}$

Divide each term in $3 x = \frac{9}{16}$ by $3$ and simplify.

Divide each term in $3 x = \frac{9}{16}$ by $3$ .

$\frac{3 x}{3} = \frac{\frac{9}{16}}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{\frac{9}{16}}{3}$

Divide $x$ by $1$ .

$x = \frac{\frac{9}{16}}{3}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{9}{16} \cdot \frac{1}{3}$

Cancel the common factor of $3$ .

Factor $3$ out of $9$ .

$x = \frac{3 (3)}{16} \cdot \frac{1}{3}$

Cancel the common factor.

$x = \frac{3 \cdot 3}{16} \cdot \frac{1}{3}$

Rewrite the expression.

$x = \frac{3}{16}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{3}{16}$

Decimal Form:

$x = 0.1875$

Solve for x square root of 3x-3/4=0

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