Solve for x square root of -4x+1+ square root of 2x+4=3

$\sqrt{- 4 x + 1} + \sqrt{2 x + 4} = 3$

Step 1

Solve for $\sqrt{- 4 x + 1}$ .

Factor $2$ out of $2 x + 4$ .

Factor $2$ out of $2 x$ .

$\sqrt{- 4 x + 1} + \sqrt{2 (x) + 4} = 3$

Factor $2$ out of $4$ .

$\sqrt{- 4 x + 1} + \sqrt{2 x + 2 \cdot 2} = 3$

Factor $2$ out of $2 x + 2 \cdot 2$ .

$\sqrt{- 4 x + 1} + \sqrt{2 (x + 2)} = 3$

Subtract $\sqrt{2 (x + 2)}$ from both sides of the equation.

$\sqrt{- 4 x + 1} = 3 - \sqrt{2 (x + 2)}$

Step 2

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{- 4 x + 1}}^{2} = {(3 - \sqrt{2 (x + 2)})}^{2}$

Step 3

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{- 4 x + 1}$ as ${(- 4 x + 1)}^{\frac{1}{2}}$ .

${({(- 4 x + 1)}^{\frac{1}{2}})}^{2} = {(3 - \sqrt{2 (x + 2)})}^{2}$

Simplify the left side.

Simplify ${({(- 4 x + 1)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(- 4 x + 1)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(- 4 x + 1)}^{\frac{1}{2} \cdot 2} = {(3 - \sqrt{2 (x + 2)})}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(- 4 x + 1)}^{\frac{1}{2} \cdot 2} = {(3 - \sqrt{2 (x + 2)})}^{2}$

Rewrite the expression.

${(- 4 x + 1)}^{1} = {(3 - \sqrt{2 (x + 2)})}^{2}$

Simplify.

$- 4 x + 1 = {(3 - \sqrt{2 (x + 2)})}^{2}$

Simplify the right side.

Simplify ${(3 - \sqrt{2 (x + 2)})}^{2}$ .

Rewrite ${(3 - \sqrt{2 (x + 2)})}^{2}$ as $(3 - \sqrt{2 (x + 2)}) (3 - \sqrt{2 (x + 2)})$ .

$- 4 x + 1 = (3 - \sqrt{2 (x + 2)}) (3 - \sqrt{2 (x + 2)})$

Expand $(3 - \sqrt{2 (x + 2)}) (3 - \sqrt{2 (x + 2)})$ using the FOIL Method.

Apply the distributive property.

$- 4 x + 1 = 3 (3 - \sqrt{2 (x + 2)}) - \sqrt{2 (x + 2)} (3 - \sqrt{2 (x + 2)})$

Apply the distributive property.

$- 4 x + 1 = 3 \cdot 3 + 3 (- \sqrt{2 (x + 2)}) - \sqrt{2 (x + 2)} (3 - \sqrt{2 (x + 2)})$

Apply the distributive property.

$- 4 x + 1 = 3 \cdot 3 + 3 (- \sqrt{2 (x + 2)}) - \sqrt{2 (x + 2)} \cdot 3 - \sqrt{2 (x + 2)} (- \sqrt{2 (x + 2)})$

Simplify and combine like terms.

Simplify each term.

Multiply $3$ by $3$ .

$- 4 x + 1 = 9 + 3 (- \sqrt{2 (x + 2)}) - \sqrt{2 (x + 2)} \cdot 3 - \sqrt{2 (x + 2)} (- \sqrt{2 (x + 2)})$

Multiply $- 1$ by $3$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - \sqrt{2 (x + 2)} \cdot 3 - \sqrt{2 (x + 2)} (- \sqrt{2 (x + 2)})$

Multiply $3$ by $- 1$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} - \sqrt{2 (x + 2)} (- \sqrt{2 (x + 2)})$

Multiply $- \sqrt{2 (x + 2)} (- \sqrt{2 (x + 2)})$ .

Multiply $- 1$ by $- 1$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + 1 \sqrt{2 (x + 2)} \sqrt{2 (x + 2)}$

Multiply $\sqrt{2 (x + 2)}$ by $1$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + \sqrt{2 (x + 2)} \sqrt{2 (x + 2)}$

Raise $\sqrt{2 (x + 2)}$ to the power of $1$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + {\sqrt{2 (x + 2)}}^{1} \sqrt{2 (x + 2)}$

Raise $\sqrt{2 (x + 2)}$ to the power of $1$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + {\sqrt{2 (x + 2)}}^{1} {\sqrt{2 (x + 2)}}^{1}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + {\sqrt{2 (x + 2)}}^{1 + 1}$

Add $1$ and $1$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + {\sqrt{2 (x + 2)}}^{2}$

Rewrite ${\sqrt{2 (x + 2)}}^{2}$ as $2 (x + 2)$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2 (x + 2)}$ as ${(2 (x + 2))}^{\frac{1}{2}}$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + {({(2 (x + 2))}^{\frac{1}{2}})}^{2}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + {(2 (x + 2))}^{\frac{1}{2} \cdot 2}$

Combine $\frac{1}{2}$ and $2$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + {(2 (x + 2))}^{\frac{2}{2}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + {(2 (x + 2))}^{\frac{2}{2}}$

Rewrite the expression.

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + {(2 (x + 2))}^{1}$

Simplify.

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + 2 (x + 2)$

Apply the distributive property.

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + 2 x + 2 \cdot 2$

Multiply $2$ by $2$ .

$- 4 x + 1 = 9 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + 2 x + 4$

Add $9$ and $4$ .

$- 4 x + 1 = 13 - 3 \sqrt{2 (x + 2)} - 3 \sqrt{2 (x + 2)} + 2 x$

Subtract $3 \sqrt{2 (x + 2)}$ from $- 3 \sqrt{2 (x + 2)}$ .

$- 4 x + 1 = 13 - 6 \sqrt{2 (x + 2)} + 2 x$

Step 4

Solve for $- 6 \sqrt{2 (x + 2)}$ .

Rewrite the equation as $13 - 6 \sqrt{2 (x + 2)} + 2 x = - 4 x + 1$ .

$13 - 6 \sqrt{2 (x + 2)} + 2 x = - 4 x + 1$

Move all terms not containing $- 6 \sqrt{2 (x + 2)}$ to the right side of the equation.

Subtract $13$ from both sides of the equation.

$- 6 \sqrt{2 (x + 2)} + 2 x = - 4 x + 1 - 13$

Subtract $2 x$ from both sides of the equation.

$- 6 \sqrt{2 (x + 2)} = - 4 x + 1 - 13 - 2 x$

Subtract $2 x$ from $- 4 x$ .

$- 6 \sqrt{2 (x + 2)} = - 6 x + 1 - 13$

Subtract $13$ from $1$ .

$- 6 \sqrt{2 (x + 2)} = - 6 x - 12$

Step 5

To remove the radical on the left side of the equation, square both sides of the equation.

${(- 6 \sqrt{2 (x + 2)})}^{2} = {(- 6 x - 12)}^{2}$

Step 6

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2 (x + 2)}$ as ${(2 (x + 2))}^{\frac{1}{2}}$ .

${(- 6 {(2 (x + 2))}^{\frac{1}{2}})}^{2} = {(- 6 x - 12)}^{2}$

Simplify the left side.

Simplify ${(- 6 {(2 (x + 2))}^{\frac{1}{2}})}^{2}$ .

Apply the distributive property.

${(- 6 {(2 x + 2 \cdot 2)}^{\frac{1}{2}})}^{2} = {(- 6 x - 12)}^{2}$

Simplify the expression.

Multiply $2$ by $2$ .

${(- 6 {(2 x + 4)}^{\frac{1}{2}})}^{2} = {(- 6 x - 12)}^{2}$

Apply the product rule to $- 6 {(2 x + 4)}^{\frac{1}{2}}$ .

${(- 6)}^{2} {({(2 x + 4)}^{\frac{1}{2}})}^{2} = {(- 6 x - 12)}^{2}$

Raise $- 6$ to the power of $2$ .

$36 {({(2 x + 4)}^{\frac{1}{2}})}^{2} = {(- 6 x - 12)}^{2}$

Multiply the exponents in ${({(2 x + 4)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$36 {(2 x + 4)}^{\frac{1}{2} \cdot 2} = {(- 6 x - 12)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$36 {(2 x + 4)}^{\frac{1}{2} \cdot 2} = {(- 6 x - 12)}^{2}$

Rewrite the expression.

$36 {(2 x + 4)}^{1} = {(- 6 x - 12)}^{2}$

Simplify.

$36 (2 x + 4) = {(- 6 x - 12)}^{2}$

Apply the distributive property.

$36 (2 x) + 36 \cdot 4 = {(- 6 x - 12)}^{2}$

Multiply.

Multiply $2$ by $36$ .

$72 x + 36 \cdot 4 = {(- 6 x - 12)}^{2}$

Multiply $36$ by $4$ .

$72 x + 144 = {(- 6 x - 12)}^{2}$

Simplify the right side.

Simplify ${(- 6 x - 12)}^{2}$ .

Rewrite ${(- 6 x - 12)}^{2}$ as $(- 6 x - 12) (- 6 x - 12)$ .

$72 x + 144 = (- 6 x - 12) (- 6 x - 12)$

Expand $(- 6 x - 12) (- 6 x - 12)$ using the FOIL Method.

Apply the distributive property.

$72 x + 144 = - 6 x (- 6 x - 12) - 12 (- 6 x - 12)$

Apply the distributive property.

$72 x + 144 = - 6 x (- 6 x) - 6 x \cdot - 12 - 12 (- 6 x - 12)$

Apply the distributive property.

$72 x + 144 = - 6 x (- 6 x) - 6 x \cdot - 12 - 12 (- 6 x) - 12 \cdot - 12$

Simplify and combine like terms.

Simplify each term.

Rewrite using the commutative property of multiplication.

$72 x + 144 = - 6 \cdot - 6 x \cdot x - 6 x \cdot - 12 - 12 (- 6 x) - 12 \cdot - 12$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$72 x + 144 = - 6 \cdot - 6 (x \cdot x) - 6 x \cdot - 12 - 12 (- 6 x) - 12 \cdot - 12$

Multiply $x$ by $x$ .

$72 x + 144 = - 6 \cdot - 6 x^{2} - 6 x \cdot - 12 - 12 (- 6 x) - 12 \cdot - 12$

Multiply $- 6$ by $- 6$ .

$72 x + 144 = 36 x^{2} - 6 x \cdot - 12 - 12 (- 6 x) - 12 \cdot - 12$

Multiply $- 12$ by $- 6$ .

$72 x + 144 = 36 x^{2} + 72 x - 12 (- 6 x) - 12 \cdot - 12$

Multiply $- 6$ by $- 12$ .

$72 x + 144 = 36 x^{2} + 72 x + 72 x - 12 \cdot - 12$

Multiply $- 12$ by $- 12$ .

$72 x + 144 = 36 x^{2} + 72 x + 72 x + 144$

Add $72 x$ and $72 x$ .

$72 x + 144 = 36 x^{2} + 144 x + 144$

Step 7

Solve for $x$ .

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$36 x^{2} + 144 x + 144 = 72 x + 144$

Move all terms containing $x$ to the left side of the equation.

Subtract $72 x$ from both sides of the equation.

$36 x^{2} + 144 x + 144 - 72 x = 144$

Subtract $72 x$ from $144 x$ .

$36 x^{2} + 72 x + 144 = 144$

Subtract $144$ from both sides of the equation.

$36 x^{2} + 72 x + 144 - 144 = 0$

Combine the opposite terms in $36 x^{2} + 72 x + 144 - 144$ .

Subtract $144$ from $144$ .

$36 x^{2} + 72 x + 0 = 0$

Add $36 x^{2} + 72 x$ and $0$ .

$36 x^{2} + 72 x = 0$

Factor $36 x$ out of $36 x^{2} + 72 x$ .

Factor $36 x$ out of $36 x^{2}$ .

$36 x (x) + 72 x = 0$

Factor $36 x$ out of $72 x$ .

$36 x (x) + 36 x (2) = 0$

Factor $36 x$ out of $36 x (x) + 36 x (2)$ .

$36 x (x + 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x + 2 = 0$

Set $x$ equal to $0$ .

$x = 0$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

The final solution is all the values that make $36 x (x + 2) = 0$ true.

$x = 0, - 2$

Solve for x square root of -4x+1+ square root of 2x+4=3

Related Questions

Support LCMGCF.com by disabling your adblocker.