Solve for x square root of 8x-7-7=0

$\sqrt{8 x - 7} - 7 = 0$

Step 1

Add $7$ to both sides of the equation.

$\sqrt{8 x - 7} = 7$

Step 2

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{8 x - 7}}^{2} = 7^{2}$

Step 3

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{8 x - 7}$ as ${(8 x - 7)}^{\frac{1}{2}}$ .

${({(8 x - 7)}^{\frac{1}{2}})}^{2} = 7^{2}$

Simplify the left side.

Simplify ${({(8 x - 7)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(8 x - 7)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(8 x - 7)}^{\frac{1}{2} \cdot 2} = 7^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(8 x - 7)}^{\frac{1}{2} \cdot 2} = 7^{2}$

Rewrite the expression.

${(8 x - 7)}^{1} = 7^{2}$

Simplify.

$8 x - 7 = 7^{2}$

Simplify the right side.

Raise $7$ to the power of $2$ .

$8 x - 7 = 49$

Step 4

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Add $7$ to both sides of the equation.

$8 x = 49 + 7$

Add $49$ and $7$ .

$8 x = 56$

Divide each term in $8 x = 56$ by $8$ and simplify.

Divide each term in $8 x = 56$ by $8$ .

$\frac{8 x}{8} = \frac{56}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} = \frac{56}{8}$

Divide $x$ by $1$ .

$x = \frac{56}{8}$

Simplify the right side.

Divide $56$ by $8$ .

$x = 7$