Solve for x square root of x+10-9=-7

$\sqrt{x + 10 - 9} = - 7$

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{x + 10 - 9}}^{2} = {(- 7)}^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 10 - 9}$ as ${(x + 10 - 9)}^{\frac{1}{2}}$ .

${({(x + 10 - 9)}^{\frac{1}{2}})}^{2} = {(- 7)}^{2}$

Simplify the left side.

Simplify ${({(x + 10 - 9)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(x + 10 - 9)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x + 10 - 9)}^{\frac{1}{2} \cdot 2} = {(- 7)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(x + 10 - 9)}^{\frac{1}{2} \cdot 2} = {(- 7)}^{2}$

Rewrite the expression.

${(x + 10 - 9)}^{1} = {(- 7)}^{2}$

Subtract $9$ from $10$ .

${(x + 1)}^{1} = {(- 7)}^{2}$

Simplify.

$x + 1 = {(- 7)}^{2}$

Simplify the right side.

Raise $- 7$ to the power of $2$ .

$x + 1 = 49$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$x = 49 - 1$

Subtract $1$ from $49$ .

$x = 48$

Exclude the solutions that do not make $\sqrt{x + 10 - 9} = - 7$ true.

$No solution$