Solve for x square root of x-4 = square root of 2x+9

$\sqrt{x - 4} = \sqrt{2 x + 9}$

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{x - 4}}^{2} = {\sqrt{2 x + 9}}^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x - 4}$ as ${(x - 4)}^{\frac{1}{2}}$ .

${({(x - 4)}^{\frac{1}{2}})}^{2} = {\sqrt{2 x + 9}}^{2}$

Simplify the left side.

Simplify ${({(x - 4)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(x - 4)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x - 4)}^{\frac{1}{2} \cdot 2} = {\sqrt{2 x + 9}}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(x - 4)}^{\frac{1}{2} \cdot 2} = {\sqrt{2 x + 9}}^{2}$

Rewrite the expression.

${(x - 4)}^{1} = {\sqrt{2 x + 9}}^{2}$

Simplify.

$x - 4 = {\sqrt{2 x + 9}}^{2}$

Simplify the right side.

Rewrite ${\sqrt{2 x + 9}}^{2}$ as $2 x + 9$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2 x + 9}$ as ${(2 x + 9)}^{\frac{1}{2}}$ .

$x - 4 = {({(2 x + 9)}^{\frac{1}{2}})}^{2}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x - 4 = {(2 x + 9)}^{\frac{1}{2} \cdot 2}$

Combine $\frac{1}{2}$ and $2$ .

$x - 4 = {(2 x + 9)}^{\frac{2}{2}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x - 4 = {(2 x + 9)}^{\frac{2}{2}}$

Rewrite the expression.

$x - 4 = {(2 x + 9)}^{1}$

Simplify.

$x - 4 = 2 x + 9$

Solve for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$x - 4 - 2 x = 9$

Subtract $2 x$ from $x$ .

$- x - 4 = 9$

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$- x = 9 + 4$

Add $9$ and $4$ .

$- x = 13$

Divide each term in $- x = 13$ by $- 1$ and simplify.

Divide each term in $- x = 13$ by $- 1$ .

$\frac{- x}{- 1} = \frac{13}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{13}{- 1}$

Divide $x$ by $1$ .

$x = \frac{13}{- 1}$

Simplify the right side.

Divide $13$ by $- 1$ .

$x = - 13$

Exclude the solutions that do not make $\sqrt{x - 4} = \sqrt{2 x + 9}$ true.

$No solution$

Solve for x square root of x-4 = square root of 2x+9

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