Solve for x square root of x+4 = square root of x+20

$\sqrt{x + 4} = \sqrt{x + 20}$

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{x + 4}}^{2} = {\sqrt{x + 20}}^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 4}$ as ${(x + 4)}^{\frac{1}{2}}$ .

${({(x + 4)}^{\frac{1}{2}})}^{2} = {\sqrt{x + 20}}^{2}$

Simplify the left side.

Simplify ${({(x + 4)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(x + 4)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x + 4)}^{\frac{1}{2} \cdot 2} = {\sqrt{x + 20}}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(x + 4)}^{\frac{1}{2} \cdot 2} = {\sqrt{x + 20}}^{2}$

Rewrite the expression.

${(x + 4)}^{1} = {\sqrt{x + 20}}^{2}$

Simplify.

$x + 4 = {\sqrt{x + 20}}^{2}$

Simplify the right side.

Rewrite ${\sqrt{x + 20}}^{2}$ as $x + 20$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 20}$ as ${(x + 20)}^{\frac{1}{2}}$ .

$x + 4 = {({(x + 20)}^{\frac{1}{2}})}^{2}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x + 4 = {(x + 20)}^{\frac{1}{2} \cdot 2}$

Combine $\frac{1}{2}$ and $2$ .

$x + 4 = {(x + 20)}^{\frac{2}{2}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x + 4 = {(x + 20)}^{\frac{2}{2}}$

Rewrite the expression.

$x + 4 = {(x + 20)}^{1}$

Simplify.

$x + 4 = x + 20$

Solve for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$x + 4 - x = 20$

Combine the opposite terms in $x + 4 - x$ .

Subtract $x$ from $x$ .

$0 + 4 = 20$

Add $0$ and $4$ .

$4 = 20$

Since $4 \neq 20$ , there are no solutions.

No solution