Solve for x square root of x-5-7=0

$\sqrt{x - 5 - 7} = 0$

Step 1

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{x - 5 - 7}}^{2} = 0^{2}$

Step 2

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x - 5 - 7}$ as ${(x - 5 - 7)}^{\frac{1}{2}}$ .

${({(x - 5 - 7)}^{\frac{1}{2}})}^{2} = 0^{2}$

Simplify the left side.

Simplify ${({(x - 5 - 7)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(x - 5 - 7)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x - 5 - 7)}^{\frac{1}{2} \cdot 2} = 0^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(x - 5 - 7)}^{\frac{1}{2} \cdot 2} = 0^{2}$

Rewrite the expression.

${(x - 5 - 7)}^{1} = 0^{2}$

Subtract $7$ from $- 5$ .

${(x - 12)}^{1} = 0^{2}$

Simplify.

$x - 12 = 0^{2}$

Simplify the right side.

Raising $0$ to any positive power yields $0$ .

$x - 12 = 0$

Step 3

Add $12$ to both sides of the equation.

$x = 12$