Solve for x square root of x>9

$\sqrt{x} > 9$

Step 1

To remove the radical on the left side of the inequality, square both sides of the inequality.

${\sqrt{x}}^{2} > 9^{2}$

Step 2

Simplify each side of the inequality.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

${(x^{\frac{1}{2}})}^{2} > 9^{2}$

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} > 9^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} > 9^{2}$

Rewrite the expression.

$x^{1} > 9^{2}$

Simplify.

$x > 9^{2}$

Simplify the right side.

Raise $9$ to the power of $2$ .

$x > 81$

Step 3

Find the domain of $\sqrt{x} - 9$ .

Set the radicand in $\sqrt{x}$ greater than or equal to $0$ to find where the expression is defined.

$x \geq 0$

The domain is all values of $x$ that make the expression defined.

$[0, \infty)$

Step 4

The solution consists of all of the true intervals.

$x > 81$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$x > 81$

Interval Notation:

$(81, \infty)$

Step 6