Solve for x tan(x)^2=0

$\tan^{2} (x) = 0$

Step 1

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$\tan (x) = \pm \sqrt{0}$

Step 2

Simplify $\pm \sqrt{0}$ .

Rewrite $0$ as $0^{2}$ .

$\tan (x) = \pm \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$\tan (x) = \pm 0$

Plus or minus $0$ is $0$ .

$\tan (x) = 0$

Step 3

Take the inverse tangent of both sides of the equation to extract $x$ from inside the tangent.

$x = \arctan (0)$

Step 4

Simplify the right side.

The exact value of $\arctan (0)$ is $0$ .

$x = 0$

Step 5

The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from $π$ to find the solution in the fourth quadrant.

$x = π + 0$

Step 6

Add $π$ and $0$ .

$x = π$

Step 7

Find the period of $\tan (x)$ .

The period of the function can be calculated using $\frac{π}{| b |}$ .

$\frac{π}{| b |}$

Replace $b$ with $1$ in the formula for period.

$\frac{π}{| 1 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{π}{1}$

Divide $π$ by $1$ .

$π$

Step 8

The period of the $\tan (x)$ function is $π$ so values will repeat every $π$ radians in both directions.

$x = π n, π + π n$ , for any integer $n$

Step 9

Consolidate the answers.

$x = π n$ , for any integer $n$

Solve for x tan(x)^2=0

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