Solve for x x+(1/2x+3)=180

$x + (\frac{1}{2} x + 3) = 180$

Simplify $x + \frac{1}{2} x + 3$ .

Combine $\frac{1}{2}$ and $x$ .

$x + \frac{x}{2} + 3 = 180$

To write $x$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x \cdot \frac{2}{2} + \frac{x}{2} + 3 = 180$

Combine $x$ and $\frac{2}{2}$ .

$\frac{x \cdot 2}{2} + \frac{x}{2} + 3 = 180$

Combine the numerators over the common denominator.

$\frac{x \cdot 2 + x}{2} + 3 = 180$

Add $x \cdot 2$ and $x$ .

Reorder $x$ and $2$ .

$\frac{2 \cdot x + x}{2} + 3 = 180$

Add $2 \cdot x$ and $x$ .

$\frac{3 \cdot x}{2} + 3 = 180$

$\frac{3 x}{2} + 3 = 180$

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$\frac{3 x}{2} = 180 - 3$

Subtract $3$ from $180$ .

$\frac{3 x}{2} = 177$

Multiply both sides of the equation by $\frac{2}{3}$ .

$\frac{2}{3} \cdot \frac{3 x}{2} = \frac{2}{3} \cdot 177$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{2}{3} \cdot \frac{3 x}{2}$ .

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2}{3} \cdot \frac{3 x}{2} = \frac{2}{3} \cdot 177$

Rewrite the expression.

$\frac{1}{3} (3 x) = \frac{2}{3} \cdot 177$

Cancel the common factor of $3$ .

Factor $3$ out of $3 x$ .

$\frac{1}{3} (3 (x)) = \frac{2}{3} \cdot 177$

Cancel the common factor.

$\frac{1}{3} (3 x) = \frac{2}{3} \cdot 177$

Rewrite the expression.

$x = \frac{2}{3} \cdot 177$

Simplify the right side.

Simplify $\frac{2}{3} \cdot 177$ .

Cancel the common factor of $3$ .

Factor $3$ out of $177$ .

$x = \frac{2}{3} \cdot (3 (59))$

Cancel the common factor.

$x = \frac{2}{3} \cdot (3 \cdot 59)$

Rewrite the expression.

$x = 2 \cdot 59$

Multiply $2$ by $59$ .

$x = 118$

Solve for x x+(1/2x+3)=180

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