Solve for x x+1/4x=15

$x + \frac{1}{4} x = 15$

Simplify $x + \frac{1}{4} x$ .

Combine $\frac{1}{4}$ and $x$ .

$x + \frac{x}{4} = 15$

To write $x$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$x \cdot \frac{4}{4} + \frac{x}{4} = 15$

Simplify terms.

Combine $x$ and $\frac{4}{4}$ .

$\frac{x \cdot 4}{4} + \frac{x}{4} = 15$

Combine the numerators over the common denominator.

$\frac{x \cdot 4 + x}{4} = 15$

Simplify the numerator.

Move $4$ to the left of $x$ .

$\frac{4 \cdot x + x}{4} = 15$

Add $4 x$ and $x$ .

$\frac{5 x}{4} = 15$

Multiply both sides of the equation by $\frac{4}{5}$ .

$\frac{4}{5} \cdot \frac{5 x}{4} = \frac{4}{5} \cdot 15$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{5} \cdot \frac{5 x}{4}$ .

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4}{5} \cdot \frac{5 x}{4} = \frac{4}{5} \cdot 15$

Rewrite the expression.

$\frac{1}{5} (5 x) = \frac{4}{5} \cdot 15$

Cancel the common factor of $5$ .

Factor $5$ out of $5 x$ .

$\frac{1}{5} (5 (x)) = \frac{4}{5} \cdot 15$

Cancel the common factor.

$\frac{1}{5} (5 x) = \frac{4}{5} \cdot 15$

Rewrite the expression.

$x = \frac{4}{5} \cdot 15$

Simplify the right side.

Simplify $\frac{4}{5} \cdot 15$ .

Cancel the common factor of $5$ .

Factor $5$ out of $15$ .

$x = \frac{4}{5} \cdot (5 (3))$

Cancel the common factor.

$x = \frac{4}{5} \cdot (5 \cdot 3)$

Rewrite the expression.

$x = 4 \cdot 3$

Multiply $4$ by $3$ .

$x = 12$