Solve for x -(x+1)-5>10

$- (x + 1) - 5 > 10$

Step 1

Simplify $- (x + 1) - 5$ .

Simplify each term.

Apply the distributive property.

$- x - 1 \cdot 1 - 5 > 10$

Multiply $- 1$ by $1$ .

$- x - 1 - 5 > 10$

Subtract $5$ from $- 1$ .

$- x - 6 > 10$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Add $6$ to both sides of the inequality.

$- x > 10 + 6$

Add $10$ and $6$ .

$- x > 16$

Step 3

Divide each term in $- x > 16$ by $- 1$ and simplify.

Divide each term in $- x > 16$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} < \frac{16}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} < \frac{16}{- 1}$

Divide $x$ by $1$ .

$x < \frac{16}{- 1}$

Simplify the right side.

Divide $16$ by $- 1$ .

$x < - 16$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x < - 16$

Interval Notation:

$(- \infty, - 16)$

Solve for x -(x+1)-5>10

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