Solve for x (x-1)(x-1)(x-1)=y

$(x - 1) (x - 1) (x - 1) = y$

Step 1

Simplify $(x - 1) (x - 1) (x - 1)$ .

Multiply $x - 1$ by $x - 1$ .

${(x - 1)}^{2} (x - 1) = y$

Multiply ${(x - 1)}^{2}$ by $x - 1$ by adding the exponents.

Multiply ${(x - 1)}^{2}$ by $x - 1$ .

Raise $x - 1$ to the power of $1$ .

${(x - 1)}^{2} {(x - 1)}^{1} = y$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

${(x - 1)}^{2 + 1} = y$

Add $2$ and $1$ .

${(x - 1)}^{3} = y$

Step 2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x - 1 = \sqrt[3]{y}$

Step 3

Add $1$ to both sides of the equation.

$x = \sqrt[3]{y} + 1$