Solve for x (x+10)(x-5)=(x+1)^2

$(x + 10) (x - 5) = {(x + 1)}^{2}$

Step 1

Simplify $(x + 10) (x - 5)$ .

Start simplifying.

$0 + 0 + (x + 10) (x - 5) = {(x + 1)}^{2}$

Simplify by adding zeros.

$(x + 10) (x - 5) = {(x + 1)}^{2}$

Expand $(x + 10) (x - 5)$ using the FOIL Method.

Apply the distributive property.

$x (x - 5) + 10 (x - 5) = {(x + 1)}^{2}$

Apply the distributive property.

$x \cdot x + x \cdot - 5 + 10 (x - 5) = {(x + 1)}^{2}$

Apply the distributive property.

$x \cdot x + x \cdot - 5 + 10 x + 10 \cdot - 5 = {(x + 1)}^{2}$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 5 + 10 x + 10 \cdot - 5 = {(x + 1)}^{2}$

Move $- 5$ to the left of $x$ .

$x^{2} - 5 \cdot x + 10 x + 10 \cdot - 5 = {(x + 1)}^{2}$

Multiply $10$ by $- 5$ .

$x^{2} - 5 x + 10 x - 50 = {(x + 1)}^{2}$

Add $- 5 x$ and $10 x$ .

$x^{2} + 5 x - 50 = {(x + 1)}^{2}$

Step 2

Simplify ${(x + 1)}^{2}$ .

Rewrite ${(x + 1)}^{2}$ as $(x + 1) (x + 1)$ .

$x^{2} + 5 x - 50 = (x + 1) (x + 1)$

Expand $(x + 1) (x + 1)$ using the FOIL Method.

Apply the distributive property.

$x^{2} + 5 x - 50 = x (x + 1) + 1 (x + 1)$

Apply the distributive property.

$x^{2} + 5 x - 50 = x \cdot x + x \cdot 1 + 1 (x + 1)$

Apply the distributive property.

$x^{2} + 5 x - 50 = x \cdot x + x \cdot 1 + 1 x + 1 \cdot 1$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + 5 x - 50 = x^{2} + x \cdot 1 + 1 x + 1 \cdot 1$

Multiply $x$ by $1$ .

$x^{2} + 5 x - 50 = x^{2} + x + 1 x + 1 \cdot 1$

Multiply $x$ by $1$ .

$x^{2} + 5 x - 50 = x^{2} + x + x + 1 \cdot 1$

Multiply $1$ by $1$ .

$x^{2} + 5 x - 50 = x^{2} + x + x + 1$

Add $x$ and $x$ .

$x^{2} + 5 x - 50 = x^{2} + 2 x + 1$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $x^{2}$ from both sides of the equation.

$x^{2} + 5 x - 50 - x^{2} = 2 x + 1$

Subtract $2 x$ from both sides of the equation.

$x^{2} + 5 x - 50 - x^{2} - 2 x = 1$

Combine the opposite terms in $x^{2} + 5 x - 50 - x^{2} - 2 x$ .

Subtract $x^{2}$ from $x^{2}$ .

$5 x - 50 + 0 - 2 x = 1$

Add $5 x - 50$ and $0$ .

$5 x - 50 - 2 x = 1$

Subtract $2 x$ from $5 x$ .

$3 x - 50 = 1$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $50$ to both sides of the equation.

$3 x = 1 + 50$

Add $1$ and $50$ .

$3 x = 51$

Step 5

Divide each term in $3 x = 51$ by $3$ and simplify.

Divide each term in $3 x = 51$ by $3$ .

$\frac{3 x}{3} = \frac{51}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{51}{3}$

Divide $x$ by $1$ .

$x = \frac{51}{3}$

Simplify the right side.

Divide $51$ by $3$ .

$x = 17$

Solve for x (x+10)(x-5)=(x+1)^2

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