Solve for x x/2+1/3<=0

$\frac{x}{2} + \frac{1}{3} \leq 0$

Subtract $\frac{1}{3}$ from both sides of the inequality.

$\frac{x}{2} \leq - \frac{1}{3}$

Multiply both sides by $2$ .

$\frac{x}{2} \cdot 2 \leq - \frac{1}{3} \cdot 2$

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{x}{2} \cdot 2 \leq - \frac{1}{3} \cdot 2$

Rewrite the expression.

$x \leq - \frac{1}{3} \cdot 2$

$x \leq - \frac{1}{3} \cdot 2$

$x \leq - \frac{1}{3} \cdot 2$

Simplify the right side.

Simplify $- \frac{1}{3} \cdot 2$ .

Multiply $- \frac{1}{3} \cdot 2$ .

Multiply $2$ by $- 1$ .

$x \leq - 2 (\frac{1}{3})$

Combine $- 2$ and $\frac{1}{3}$ .

$x \leq \frac{- 2}{3}$

$x \leq \frac{- 2}{3}$

Move the negative in front of the fraction.

$x \leq - \frac{2}{3}$

$x \leq - \frac{2}{3}$

$x \leq - \frac{2}{3}$

$x \leq - \frac{2}{3}$

The result can be shown in multiple forms.

Inequality Form:

$x \leq - \frac{2}{3}$

Interval Notation:

$(- \infty, - \frac{2}{3}]$

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