Solve for x x^2+11x+15=-3

$x^{2} + 11 x + 15 = - 3$

Step 1

Add $3$ to both sides of the equation.

$x^{2} + 11 x + 15 + 3 = 0$

Step 2

Add $15$ and $3$ .

$x^{2} + 11 x + 18 = 0$

Step 3

Factor $x^{2} + 11 x + 18$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $18$ and whose sum is $11$ .

$2, 9$

Write the factored form using these integers.

$(x + 2) (x + 9) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 2 = 0$

$x + 9 = 0$

Step 5

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

Step 6

Set $x + 9$ equal to $0$ and solve for $x$ .

Set $x + 9$ equal to $0$ .

$x + 9 = 0$

Subtract $9$ from both sides of the equation.

$x = - 9$

Step 7

The final solution is all the values that make $(x + 2) (x + 9) = 0$ true.

$x = - 2, - 9$

Solve for x x^2+11x+15=-3

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