Solve for x x^2+14-x=-10x

$x^{2} + 14 - x = - 10 x$

Move all terms containing $x$ to the left side of the equation.

Add $10 x$ to both sides of the equation.

$x^{2} + 14 - x + 10 x = 0$

Add $- x$ and $10 x$ .

$x^{2} + 14 + 9 x = 0$

Factor $x^{2} + 14 + 9 x$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $14$ and whose sum is $9$ .

$2, 7$

Write the factored form using these integers.

$(x + 2) (x + 7) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 2 = 0$

$x + 7 = 0$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

Set $x + 7$ equal to $0$ and solve for $x$ .

Set $x + 7$ equal to $0$ .

$x + 7 = 0$

Subtract $7$ from both sides of the equation.

$x = - 7$

The final solution is all the values that make $(x + 2) (x + 7) = 0$ true.

$x = - 2, - 7$

Solve for x x^2+14-x=-10x

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