Solve for x x^2-16<0

$x^{2} - 16 < 0$

Step 1

Add $16$ to both sides of the inequality.

$x^{2} < 16$

Step 2

Take the specified root of both sides of the inequality to eliminate the exponent on the left side.

$\sqrt{x^{2}} < \sqrt{16}$

Step 3

Simplify the equation.

Simplify the left side.

Pull terms out from under the radical.

$| x | < \sqrt{16}$

Simplify the right side.

Simplify $\sqrt{16}$ .

Rewrite $16$ as $4^{2}$ .

$| x | < \sqrt{4^{2}}$

Pull terms out from under the radical.

$| x | < | 4 |$

The absolute value is the distance between a number and zero. The distance between $0$ and $4$ is $4$ .

$| x | < 4$

Step 4

Write $| x | < 4$ as a piecewise.

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$x \geq 0$

In the piece where $x$ is non-negative, remove the absolute value.

$x < 4$

To find the interval for the second piece, find where the inside of the absolute value is negative.

$x < 0$

In the piece where $x$ is negative, remove the absolute value and multiply by $- 1$ .

$- x < 4$

Write as a piecewise.

${\begin{cases} x < 4 & x \geq 0 \\ - x < 4 & x < 0 \end{cases}$

Step 5

Find the intersection of $x < 4$ and $x \geq 0$ .

$0 \leq x < 4$

Step 6

Solve $- x < 4$ when $x < 0$ .

Divide each term in $- x < 4$ by $- 1$ and simplify.

Divide each term in $- x < 4$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} > \frac{4}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} > \frac{4}{- 1}$

Divide $x$ by $1$ .

$x > \frac{4}{- 1}$

Simplify the right side.

Divide $4$ by $- 1$ .

$x > - 4$

Find the intersection of $x > - 4$ and $x < 0$ .

$- 4 < x < 0$

Step 7

Find the union of the solutions.

$- 4 < x < 4$

Step 8

The result can be shown in multiple forms.

Inequality Form:

$- 4 < x < 4$

Interval Notation:

$(- 4, 4)$

Step 9

Solve for x x^2-16<0

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