Solve for x |x-2|+2<3

$| x - 2 | + 2 < 3$

Step 1

Write $| x - 2 | + 2 < 3$ as a piecewise.

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$x - 2 \geq 0$

Add $2$ to both sides of the inequality.

$x \geq 2$

In the piece where $x - 2$ is non-negative, remove the absolute value.

$x - 2 + 2 < 3$

To find the interval for the second piece, find where the inside of the absolute value is negative.

$x - 2 < 0$

Add $2$ to both sides of the inequality.

$x < 2$

In the piece where $x - 2$ is negative, remove the absolute value and multiply by $- 1$ .

$- (x - 2) + 2 < 3$

Write as a piecewise.

${\begin{cases} x - 2 + 2 < 3 & x \geq 2 \\ - (x - 2) + 2 < 3 & x < 2 \end{cases}$

Combine the opposite terms in $x - 2 + 2$ .

Add $- 2$ and $2$ .

${\begin{cases} x + 0 < 3 & x \geq 2 \\ - (x - 2) + 2 < 3 & x < 2 \end{cases}$

Add $x$ and $0$ .

${\begin{cases} x < 3 & x \geq 2 \\ - (x - 2) + 2 < 3 & x < 2 \end{cases}$

Simplify $- (x - 2) + 2 < 3$ .

Simplify each term.

Apply the distributive property.

${\begin{cases} x < 3 & x \geq 2 \\ - x - - 2 + 2 < 3 & x < 2 \end{cases}$

Multiply $- 1$ by $- 2$ .

${\begin{cases} x < 3 & x \geq 2 \\ - x + 2 + 2 < 3 & x < 2 \end{cases}$

Add $2$ and $2$ .

${\begin{cases} x < 3 & x \geq 2 \\ - x + 4 < 3 & x < 2 \end{cases}$

Step 2

Find the intersection of $x < 3$ and $x \geq 2$ .

$2 \leq x < 3$

Step 3

Solve $- x + 4 < 3$ when $x < 2$ .

Solve $- x + 4 < 3$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Subtract $4$ from both sides of the inequality.

$- x < 3 - 4$

Subtract $4$ from $3$ .

$- x < - 1$

Divide each term in $- x < - 1$ by $- 1$ and simplify.

Divide each term in $- x < - 1$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} > \frac{- 1}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} > \frac{- 1}{- 1}$

Divide $x$ by $1$ .

$x > \frac{- 1}{- 1}$

Simplify the right side.

Divide $- 1$ by $- 1$ .

$x > 1$

Find the intersection of $x > 1$ and $x < 2$ .

$1 < x < 2$

Step 4

Find the union of the solutions.

$1 < x < 3$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$1 < x < 3$

Interval Notation:

$(1, 3)$

Step 6

Solve for x |x-2|+2<3

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