Solve for x x^2+2x-10=0

$x^{2} + 2 x - 10 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 1$ , $b = 2$ , and $c = - 10$ into the quadratic formula and solve for $x$ .

$\frac{- 2 \pm \sqrt{2^{2} - 4 \cdot (1 \cdot - 10)}}{2 \cdot 1}$

Step 3

Simplify.

Simplify the numerator.

Raise $2$ to the power of $2$ .

$x = \frac{- 2 \pm \sqrt{4 - 4 \cdot 1 \cdot - 10}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot - 10$ .

Multiply $- 4$ by $1$ .

$x = \frac{- 2 \pm \sqrt{4 - 4 \cdot - 10}}{2 \cdot 1}$

Multiply $- 4$ by $- 10$ .

$x = \frac{- 2 \pm \sqrt{4 + 40}}{2 \cdot 1}$

Add $4$ and $40$ .

$x = \frac{- 2 \pm \sqrt{44}}{2 \cdot 1}$

Rewrite $44$ as $2^{2} \cdot 11$ .

Factor $4$ out of $44$ .

$x = \frac{- 2 \pm \sqrt{4 (11)}}{2 \cdot 1}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{- 2 \pm \sqrt{2^{2} \cdot 11}}{2 \cdot 1}$

Pull terms out from under the radical.

$x = \frac{- 2 \pm 2 \sqrt{11}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$x = \frac{- 2 \pm 2 \sqrt{11}}{2}$

Simplify $\frac{- 2 \pm 2 \sqrt{11}}{2}$ .

$x = - 1 \pm \sqrt{11}$

Step 4

The final answer is the combination of both solutions.

$x = - 1 + \sqrt{11}, - 1 - \sqrt{11}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = - 1 + \sqrt{11}, - 1 - \sqrt{11}$

Decimal Form:

$x = 2.31662479 \dots, - 4.31662479 \dots$