Solve for x x^2+2x-36=2x

$x^{2} + 2 x - 36 = 2 x$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$x^{2} + 2 x - 36 - 2 x = 0$

Combine the opposite terms in $x^{2} + 2 x - 36 - 2 x$ .

Subtract $2 x$ from $2 x$ .

$x^{2} + 0 - 36 = 0$

Add $x^{2}$ and $0$ .

$x^{2} - 36 = 0$

Add $36$ to both sides of the equation.

$x^{2} = 36$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{36}$

Simplify $\pm \sqrt{36}$ .

Rewrite $36$ as $6^{2}$ .

$x = \pm \sqrt{6^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 6$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 6$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 6$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 6, - 6$