Solve for x (x^2-3)/(x+2)=(x-3)/2

$\frac{x^{2} - 3}{x + 2} = \frac{x - 3}{2}$

Step 1

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

$(x^{2} - 3) \cdot 2 = (x + 2) (x - 3)$

Step 2

Solve the equation for $x$ .

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$(x + 2) (x - 3) = (x^{2} - 3) \cdot 2$

Simplify $(x + 2) (x - 3)$ .

Start simplifying.

$0 + 0 + (x + 2) (x - 3) = (x^{2} - 3) \cdot 2$

Simplify by adding zeros.

$(x + 2) (x - 3) = (x^{2} - 3) \cdot 2$

Expand $(x + 2) (x - 3)$ using the FOIL Method.

Apply the distributive property.

$x (x - 3) + 2 (x - 3) = (x^{2} - 3) \cdot 2$

Apply the distributive property.

$x \cdot x + x \cdot - 3 + 2 (x - 3) = (x^{2} - 3) \cdot 2$

Apply the distributive property.

$x \cdot x + x \cdot - 3 + 2 x + 2 \cdot - 3 = (x^{2} - 3) \cdot 2$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 3 + 2 x + 2 \cdot - 3 = (x^{2} - 3) \cdot 2$

Move $- 3$ to the left of $x$ .

$x^{2} - 3 \cdot x + 2 x + 2 \cdot - 3 = (x^{2} - 3) \cdot 2$

Multiply $2$ by $- 3$ .

$x^{2} - 3 x + 2 x - 6 = (x^{2} - 3) \cdot 2$

Add $- 3 x$ and $2 x$ .

$x^{2} - x - 6 = (x^{2} - 3) \cdot 2$

Simplify $(x^{2} - 3) \cdot 2$ .

Apply the distributive property.

$x^{2} - x - 6 = x^{2} \cdot 2 - 3 \cdot 2$

Simplify the expression.

Move $2$ to the left of $x^{2}$ .

$x^{2} - x - 6 = 2 \cdot x^{2} - 3 \cdot 2$

Multiply $- 3$ by $2$ .

$x^{2} - x - 6 = 2 x^{2} - 6$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x^{2}$ from both sides of the equation.

$x^{2} - x - 6 - 2 x^{2} = - 6$

Subtract $2 x^{2}$ from $x^{2}$ .

$- x^{2} - x - 6 = - 6$

Add $6$ to both sides of the equation.

$- x^{2} - x - 6 + 6 = 0$

Combine the opposite terms in $- x^{2} - x - 6 + 6$ .

Add $- 6$ and $6$ .

$- x^{2} - x + 0 = 0$

Add $- x^{2} - x$ and $0$ .

$- x^{2} - x = 0$

Factor $- x$ out of $- x^{2} - x$ .

Factor $- x$ out of $- x^{2}$ .

$- x \cdot x - x = 0$

Factor $- x$ out of $- x$ .

$- x \cdot x - x \cdot 1 = 0$

Factor $- x$ out of $- x (x) - x (1)$ .

$- x (x + 1) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x + 1 = 0$

Set $x$ equal to $0$ .

$x = 0$

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

The final solution is all the values that make $- x (x + 1) = 0$ true.

$x = 0, - 1$

Solve for x (x^2-3)/(x+2)=(x-3)/2

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