Solve for x x/2+3+x+9=60

$\frac{x}{2} + 3 + x + 9 = 60$

Step 1

Simplify $\frac{x}{2} + 3 + x + 9$ .

To write $x$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x}{2} + x \cdot \frac{2}{2} + 3 + 9 = 60$

Combine $x$ and $\frac{2}{2}$ .

$\frac{x}{2} + \frac{x \cdot 2}{2} + 3 + 9 = 60$

Combine the numerators over the common denominator.

$\frac{x + x \cdot 2}{2} + 3 + 9 = 60$

Add $x$ and $x \cdot 2$ .

Reorder $x$ and $2$ .

$\frac{x + 2 \cdot x}{2} + 3 + 9 = 60$

Add $x$ and $2 \cdot x$ .

$\frac{3 x}{2} + 3 + 9 = 60$

Add $3$ and $9$ .

$\frac{3 x}{2} + 12 = 60$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$\frac{3 x}{2} = 60 - 12$

Subtract $12$ from $60$ .

$\frac{3 x}{2} = 48$

Step 3

Multiply both sides of the equation by $\frac{2}{3}$ .

$\frac{2}{3} \cdot \frac{3 x}{2} = \frac{2}{3} \cdot 48$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{2}{3} \cdot \frac{3 x}{2}$ .

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2}{3} \cdot \frac{3 x}{2} = \frac{2}{3} \cdot 48$

Rewrite the expression.

$\frac{1}{3} (3 x) = \frac{2}{3} \cdot 48$

Cancel the common factor of $3$ .

Factor $3$ out of $3 x$ .

$\frac{1}{3} (3 (x)) = \frac{2}{3} \cdot 48$

Cancel the common factor.

$\frac{1}{3} (3 x) = \frac{2}{3} \cdot 48$

Rewrite the expression.

$x = \frac{2}{3} \cdot 48$

Simplify the right side.

Simplify $\frac{2}{3} \cdot 48$ .

Cancel the common factor of $3$ .

Factor $3$ out of $48$ .

$x = \frac{2}{3} \cdot (3 (16))$

Cancel the common factor.

$x = \frac{2}{3} \cdot (3 \cdot 16)$

Rewrite the expression.

$x = 2 \cdot 16$

Multiply $2$ by $16$ .

$x = 32$

Solve for x x/2+3+x+9=60

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