Solve for x x^2-49<0

$x^{2} - 49 < 0$

Step 1

Add $49$ to both sides of the inequality.

$x^{2} < 49$

Step 2

Take the specified root of both sides of the inequality to eliminate the exponent on the left side.

$\sqrt{x^{2}} < \sqrt{49}$

Step 3

Simplify the equation.

Simplify the left side.

Pull terms out from under the radical.

$| x | < \sqrt{49}$

Simplify the right side.

Simplify $\sqrt{49}$ .

Rewrite $49$ as $7^{2}$ .

$| x | < \sqrt{7^{2}}$

Pull terms out from under the radical.

$| x | < | 7 |$

The absolute value is the distance between a number and zero. The distance between $0$ and $7$ is $7$ .

$| x | < 7$

Step 4

Write $| x | < 7$ as a piecewise.

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$x \geq 0$

In the piece where $x$ is non-negative, remove the absolute value.

$x < 7$

To find the interval for the second piece, find where the inside of the absolute value is negative.

$x < 0$

In the piece where $x$ is negative, remove the absolute value and multiply by $- 1$ .

$- x < 7$

Write as a piecewise.

${\begin{cases} x < 7 & x \geq 0 \\ - x < 7 & x < 0 \end{cases}$

Step 5

Find the intersection of $x < 7$ and $x \geq 0$ .

$0 \leq x < 7$

Step 6

Solve $- x < 7$ when $x < 0$ .

Divide each term in $- x < 7$ by $- 1$ and simplify.

Divide each term in $- x < 7$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} > \frac{7}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} > \frac{7}{- 1}$

Divide $x$ by $1$ .

$x > \frac{7}{- 1}$

Simplify the right side.

Divide $7$ by $- 1$ .

$x > - 7$

Find the intersection of $x > - 7$ and $x < 0$ .

$- 7 < x < 0$

Step 7

Find the union of the solutions.

$- 7 < x < 7$

Step 8

The result can be shown in multiple forms.

Inequality Form:

$- 7 < x < 7$

Interval Notation:

$(- 7, 7)$

Step 9

Solve for x x^2-49<0

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