Solve for x (x^2+4x+4)/40=(x+2)/10

$\frac{x^{2} + 4 x + 4}{40} = \frac{x + 2}{10}$

Step 1

Factor using the perfect square rule.

Rewrite $4$ as $2^{2}$ .

$\frac{x^{2} + 4 x + 2^{2}}{40} = \frac{x + 2}{10}$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$4 x = 2 \cdot x \cdot 2$

Rewrite the polynomial.

$\frac{x^{2} + 2 \cdot x \cdot 2 + 2^{2}}{40} = \frac{x + 2}{10}$

Factor using the perfect square trinomial rule $a^{2} + 2 a b + b^{2} = {(a + b)}^{2}$ , where $a = x$ and $b = 2$ .

$\frac{{(x + 2)}^{2}}{40} = \frac{x + 2}{10}$

Step 2

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

${(x + 2)}^{2} \cdot 10 = 40 (x + 2)$

Step 3

Solve the equation for $x$ .

Move $10$ to the left of ${(x + 2)}^{2}$ .

$10 {(x + 2)}^{2} = 40 (x + 2)$

Simplify $40 (x + 2)$ .

Apply the distributive property.

$10 {(x + 2)}^{2} = 40 x + 40 \cdot 2$

Multiply $40$ by $2$ .

$10 {(x + 2)}^{2} = 40 x + 80$

Move all terms containing $x$ to the left side of the equation.

Subtract $40 x$ from both sides of the equation.

$10 {(x + 2)}^{2} - 40 x = 80$

Simplify each term.

Rewrite ${(x + 2)}^{2}$ as $(x + 2) (x + 2)$ .

$10 ((x + 2) (x + 2)) - 40 x = 80$

Expand $(x + 2) (x + 2)$ using the FOIL Method.

Apply the distributive property.

$10 (x (x + 2) + 2 (x + 2)) - 40 x = 80$

Apply the distributive property.

$10 (x \cdot x + x \cdot 2 + 2 (x + 2)) - 40 x = 80$

Apply the distributive property.

$10 (x \cdot x + x \cdot 2 + 2 x + 2 \cdot 2) - 40 x = 80$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$10 (x^{2} + x \cdot 2 + 2 x + 2 \cdot 2) - 40 x = 80$

Move $2$ to the left of $x$ .

$10 (x^{2} + 2 \cdot x + 2 x + 2 \cdot 2) - 40 x = 80$

Multiply $2$ by $2$ .

$10 (x^{2} + 2 x + 2 x + 4) - 40 x = 80$

Add $2 x$ and $2 x$ .

$10 (x^{2} + 4 x + 4) - 40 x = 80$

Apply the distributive property.

$10 x^{2} + 10 (4 x) + 10 \cdot 4 - 40 x = 80$

Simplify.

Multiply $4$ by $10$ .

$10 x^{2} + 40 x + 10 \cdot 4 - 40 x = 80$

Multiply $10$ by $4$ .

$10 x^{2} + 40 x + 40 - 40 x = 80$

Combine the opposite terms in $10 x^{2} + 40 x + 40 - 40 x$ .

Subtract $40 x$ from $40 x$ .

$10 x^{2} + 0 + 40 = 80$

Add $10 x^{2}$ and $0$ .

$10 x^{2} + 40 = 80$

Move all terms not containing $x$ to the right side of the equation.

Subtract $40$ from both sides of the equation.

$10 x^{2} = 80 - 40$

Subtract $40$ from $80$ .

$10 x^{2} = 40$

Divide each term in $10 x^{2} = 40$ by $10$ and simplify.

Divide each term in $10 x^{2} = 40$ by $10$ .

$\frac{10 x^{2}}{10} = \frac{40}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 x^{2}}{10} = \frac{40}{10}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{40}{10}$

Simplify the right side.

Divide $40$ by $10$ .

$x^{2} = 4$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{4}$

Simplify $\pm \sqrt{4}$ .

Rewrite $4$ as $2^{2}$ .

$x = \pm \sqrt{2^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 2$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 2$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 2$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 2, - 2$

Solve for x (x^2+4x+4)/40=(x+2)/10

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