Solve for x x^2=6^2+8^2

$x^{2} = 6^{2} + 8^{2}$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{6^{2} + 8^{2}}$

Simplify $\pm \sqrt{6^{2} + 8^{2}}$ .

Raise $6$ to the power of $2$ .

$x = \pm \sqrt{36 + 8^{2}}$

Raise $8$ to the power of $2$ .

$x = \pm \sqrt{36 + 64}$

Add $36$ and $64$ .

$x = \pm \sqrt{100}$

Rewrite $100$ as $10^{2}$ .

$x = \pm \sqrt{10^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 10$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 10$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 10$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 10, - 10$