Solve for x x^2+6=6

$x^{2} + 6 = 6$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$x^{2} = 6 - 6$

Subtract $6$ from $6$ .

$x^{2} = 0$

Step 2

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{0}$

Step 3

Simplify $\pm \sqrt{0}$ .

Rewrite $0$ as $0^{2}$ .

$x = \pm \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 0$

Plus or minus $0$ is $0$ .

$x = 0$