Solve for x x^2+8x-3=-2x-3

$x^{2} + 8 x - 3 = - 2 x - 3$

Move all terms containing $x$ to the left side of the equation.

Add $2 x$ to both sides of the equation.

$x^{2} + 8 x - 3 + 2 x = - 3$

Add $8 x$ and $2 x$ .

$x^{2} + 10 x - 3 = - 3$

Add $3$ to both sides of the equation.

$x^{2} + 10 x - 3 + 3 = 0$

Combine the opposite terms in $x^{2} + 10 x - 3 + 3$ .

Add $- 3$ and $3$ .

$x^{2} + 10 x + 0 = 0$

Add $x^{2} + 10 x$ and $0$ .

$x^{2} + 10 x = 0$

Factor $x$ out of $x^{2} + 10 x$ .

Factor $x$ out of $x^{2}$ .

$x \cdot x + 10 x = 0$

Factor $x$ out of $10 x$ .

$x \cdot x + x \cdot 10 = 0$

Factor $x$ out of $x \cdot x + x \cdot 10$ .

$x (x + 10) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x + 10 = 0$

Set $x$ equal to $0$ .

$x = 0$

Set $x + 10$ equal to $0$ and solve for $x$ .

Set $x + 10$ equal to $0$ .

$x + 10 = 0$

Subtract $10$ from both sides of the equation.

$x = - 10$

The final solution is all the values that make $x (x + 10) = 0$ true.

$x = 0, - 10$