Solve for x x^2+8x<33

$x^{2} + 8 x < 33$

Step 1

Convert the inequality to an equation.

$x^{2} + 8 x = 33$

Step 2

Subtract $33$ from both sides of the equation.

$x^{2} + 8 x - 33 = 0$

Step 3

Factor $x^{2} + 8 x - 33$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 33$ and whose sum is $8$ .

$- 3, 11$

Write the factored form using these integers.

$(x - 3) (x + 11) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 3 = 0$

$x + 11 = 0$

Step 5

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

Step 6

Set $x + 11$ equal to $0$ and solve for $x$ .

Set $x + 11$ equal to $0$ .

$x + 11 = 0$

Subtract $11$ from both sides of the equation.

$x = - 11$

Step 7

The final solution is all the values that make $(x - 3) (x + 11) = 0$ true.

$x = 3, - 11$

Step 8

Use each root to create test intervals.

$x < - 11$

$- 11 < x < 3$

$x > 3$

Step 9

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

Test a value on the interval $x < - 11$ to see if it makes the inequality true.

Choose a value on the interval $x < - 11$ and see if this value makes the original inequality true.

$x = - 14$

Replace $x$ with $- 14$ in the original inequality.

${(- 14)}^{2} + 8 (- 14) < 33$

The left side $84$ is not less than the right side $33$ , which means that the given statement is false.

False

Test a value on the interval $- 11 < x < 3$ to see if it makes the inequality true.

Choose a value on the interval $- 11 < x < 3$ and see if this value makes the original inequality true.

$x = 0$

Replace $x$ with $0$ in the original inequality.

${(0)}^{2} + 8 (0) < 33$

The left side $0$ is less than the right side $33$ , which means that the given statement is always true.

True

Test a value on the interval $x > 3$ to see if it makes the inequality true.

Choose a value on the interval $x > 3$ and see if this value makes the original inequality true.

$x = 6$

Replace $x$ with $6$ in the original inequality.

${(6)}^{2} + 8 (6) < 33$

The left side $84$ is not less than the right side $33$ , which means that the given statement is false.

False

Compare the intervals to determine which ones satisfy the original inequality.

$x < - 11$ False

$- 11 < x < 3$ True

$x > 3$ False

$x < - 11$ False

$- 11 < x < 3$ True

$x > 3$ False

Step 10

The solution consists of all of the true intervals.

$- 11 < x < 3$

Step 11

The result can be shown in multiple forms.

Inequality Form:

$- 11 < x < 3$

Interval Notation:

$(- 11, 3)$

Step 12

Solve for x x^2+8x<33

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