Solve for x x-2(x+10)=12

$x - 2 (x + 10) = 12$

Step 1

Simplify $x - 2 (x + 10)$ .

Simplify each term.

Apply the distributive property.

$x - 2 x - 2 \cdot 10 = 12$

Multiply $- 2$ by $10$ .

$x - 2 x - 20 = 12$

Subtract $2 x$ from $x$ .

$- x - 20 = 12$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $20$ to both sides of the equation.

$- x = 12 + 20$

Add $12$ and $20$ .

$- x = 32$

Step 3

Divide each term in $- x = 32$ by $- 1$ and simplify.

Divide each term in $- x = 32$ by $- 1$ .

$\frac{- x}{- 1} = \frac{32}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{32}{- 1}$

Divide $x$ by $1$ .

$x = \frac{32}{- 1}$

Simplify the right side.

Divide $32$ by $- 1$ .

$x = - 32$