Solve for x (x+2)(x+3)=x^2-10

$(x + 2) (x + 3) = x^{2} - 10$

Simplify $(x + 2) (x + 3)$ .

Rewrite.

$0 + 0 + (x + 2) (x + 3) = x^{2} - 10$

Simplify by adding zeros.

$(x + 2) (x + 3) = x^{2} - 10$

Expand $(x + 2) (x + 3)$ using the FOIL Method.

Apply the distributive property.

$x (x + 3) + 2 (x + 3) = x^{2} - 10$

Apply the distributive property.

$x \cdot x + x \cdot 3 + 2 (x + 3) = x^{2} - 10$

Apply the distributive property.

$x \cdot x + x \cdot 3 + 2 x + 2 \cdot 3 = x^{2} - 10$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 3 + 2 x + 2 \cdot 3 = x^{2} - 10$

Move $3$ to the left of $x$ .

$x^{2} + 3 \cdot x + 2 x + 2 \cdot 3 = x^{2} - 10$

Multiply $2$ by $3$ .

$x^{2} + 3 x + 2 x + 6 = x^{2} - 10$

Add $3 x$ and $2 x$ .

$x^{2} + 5 x + 6 = x^{2} - 10$

Move all terms containing $x$ to the left side of the equation.

Subtract $x^{2}$ from both sides of the equation.

$x^{2} + 5 x + 6 - x^{2} = - 10$

Combine the opposite terms in $x^{2} + 5 x + 6 - x^{2}$ .

Subtract $x^{2}$ from $x^{2}$ .

$5 x + 6 + 0 = - 10$

Add $5 x + 6$ and $0$ .

$5 x + 6 = - 10$

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$5 x = - 10 - 6$

Subtract $6$ from $- 10$ .

$5 x = - 16$

Divide each term in $5 x = - 16$ by $5$ and simplify.

Divide each term in $5 x = - 16$ by $5$ .

$\frac{5 x}{5} = \frac{- 16}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{- 16}{5}$

Divide $x$ by $1$ .

$x = \frac{- 16}{5}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{16}{5}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{16}{5}$

Decimal Form:

$x = - 3.2$

Mixed Number Form:

$x = - 3 \frac{1}{5}$

Solve for x (x+2)(x+3)=x^2-10

Related Questions

Support LCMGCF.com by disabling your adblocker.