Solve for x x-20=(20+x)/3

$x - 20 = \frac{20 + x}{3}$

Multiply both sides by $3$ .

$(x - 20) \cdot 3 = \frac{20 + x}{3} \cdot 3$

Simplify.

Simplify the left side.

Simplify $(x - 20) \cdot 3$ .

Apply the distributive property.

$x \cdot 3 - 20 \cdot 3 = \frac{20 + x}{3} \cdot 3$

Simplify the expression.

Move $3$ to the left of $x$ .

$3 \cdot x - 20 \cdot 3 = \frac{20 + x}{3} \cdot 3$

Multiply $- 20$ by $3$ .

$3 x - 60 = \frac{20 + x}{3} \cdot 3$

Simplify the right side.

Simplify $\frac{20 + x}{3} \cdot 3$ .

Cancel the common factor of $3$ .

Cancel the common factor.

$3 x - 60 = \frac{20 + x}{3} \cdot 3$

Rewrite the expression.

$3 x - 60 = 20 + x$

Reorder $20$ and $x$ .

$3 x - 60 = x + 20$

Solve for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$3 x - 60 - x = 20$

Subtract $x$ from $3 x$ .

$2 x - 60 = 20$

Move all terms not containing $x$ to the right side of the equation.

Add $60$ to both sides of the equation.

$2 x = 20 + 60$

Add $20$ and $60$ .

$2 x = 80$

Divide each term in $2 x = 80$ by $2$ and simplify.

Divide each term in $2 x = 80$ by $2$ .

$\frac{2 x}{2} = \frac{80}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{80}{2}$

Divide $x$ by $1$ .

$x = \frac{80}{2}$

Simplify the right side.

Divide $80$ by $2$ .

$x = 40$