Solve for x -x/3-1/4x=14

$- \frac{x}{3} - \frac{1}{4} x = 14$

Simplify $- \frac{x}{3} - \frac{1}{4} x$ .

Combine $x$ and $\frac{1}{4}$ .

$- \frac{x}{3} - \frac{x}{4} = 14$

To write $- \frac{x}{3}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- \frac{x}{3} \cdot \frac{4}{4} - \frac{x}{4} = 14$

To write $- \frac{x}{4}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{x}{3} \cdot \frac{4}{4} - \frac{x}{4} \cdot \frac{3}{3} = 14$

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{x}{3}$ by $\frac{4}{4}$ .

$- \frac{x \cdot 4}{3 \cdot 4} - \frac{x}{4} \cdot \frac{3}{3} = 14$

Multiply $3$ by $4$ .

$- \frac{x \cdot 4}{12} - \frac{x}{4} \cdot \frac{3}{3} = 14$

Multiply $\frac{x}{4}$ by $\frac{3}{3}$ .

$- \frac{x \cdot 4}{12} - \frac{x \cdot 3}{4 \cdot 3} = 14$

Multiply $4$ by $3$ .

$- \frac{x \cdot 4}{12} - \frac{x \cdot 3}{12} = 14$

Combine the numerators over the common denominator.

$\frac{- x \cdot 4 - x \cdot 3}{12} = 14$

Simplify the numerator.

Factor $x$ out of $- x \cdot 4 - x \cdot 3$ .

Factor $x$ out of $- x \cdot 4$ .

$\frac{x (- 1 \cdot 4) - x \cdot 3}{12} = 14$

Factor $x$ out of $- x \cdot 3$ .

$\frac{x (- 1 \cdot 4) + x (- 1 \cdot 3)}{12} = 14$

Factor $x$ out of $x (- 1 \cdot 4) + x (- 1 \cdot 3)$ .

$\frac{x (- 1 \cdot 4 - 1 \cdot 3)}{12} = 14$

Multiply $- 1$ by $4$ .

$\frac{x (- 4 - 1 \cdot 3)}{12} = 14$

Multiply $- 1$ by $3$ .

$\frac{x (- 4 - 3)}{12} = 14$

Subtract $3$ from $- 4$ .

$\frac{x \cdot - 7}{12} = 14$

Simplify the expression.

Move $- 7$ to the left of $x$ .

$\frac{- 7 \cdot x}{12} = 14$

Move the negative in front of the fraction.

$- \frac{7 x}{12} = 14$

Multiply both sides of the equation by $- \frac{12}{7}$ .

$- \frac{12}{7} (- \frac{7 x}{12}) = - \frac{12}{7} \cdot 14$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{12}{7} (- \frac{7 x}{12})$ .

Cancel the common factor of $12$ .

Move the leading negative in $- \frac{12}{7}$ into the numerator.

$\frac{- 12}{7} (- \frac{7 x}{12}) = - \frac{12}{7} \cdot 14$

Move the leading negative in $- \frac{7 x}{12}$ into the numerator.

$\frac{- 12}{7} \cdot \frac{- 7 x}{12} = - \frac{12}{7} \cdot 14$

Factor $12$ out of $- 12$ .

$\frac{12 (- 1)}{7} \cdot \frac{- 7 x}{12} = - \frac{12}{7} \cdot 14$

Cancel the common factor.

$\frac{12 \cdot - 1}{7} \cdot \frac{- 7 x}{12} = - \frac{12}{7} \cdot 14$

Rewrite the expression.

$\frac{- 1}{7} (- 7 x) = - \frac{12}{7} \cdot 14$

Cancel the common factor of $7$ .

Factor $7$ out of $- 7 x$ .

$\frac{- 1}{7} (7 (- x)) = - \frac{12}{7} \cdot 14$

Cancel the common factor.

$\frac{- 1}{7} (7 (- x)) = - \frac{12}{7} \cdot 14$

Rewrite the expression.

$- - x = - \frac{12}{7} \cdot 14$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{12}{7} \cdot 14$

Multiply $x$ by $1$ .

$x = - \frac{12}{7} \cdot 14$

Simplify the right side.

Simplify $- \frac{12}{7} \cdot 14$ .

Cancel the common factor of $7$ .

Move the leading negative in $- \frac{12}{7}$ into the numerator.

$x = \frac{- 12}{7} \cdot 14$

Factor $7$ out of $14$ .

$x = \frac{- 12}{7} \cdot (7 (2))$

Cancel the common factor.

$x = \frac{- 12}{7} \cdot (7 \cdot 2)$

Rewrite the expression.

$x = - 12 \cdot 2$

Multiply $- 12$ by $2$ .

$x = - 24$

Solve for x -x/3-1/4x=14

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